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Varvara68 [4.7K]

3 years ago

13

Solve −4(x + 1) − 3 = −3(x − 4). −19 19 2 0

1 answer:

Effectus [21]3 years ago

8 0

-4(x + 1) - 3 = -3(x - 4)
-4(x) - 4(1) - 3 = -3(x) - 3(-4)
-4x - 4 - 3 = -3x + 12
  -4x - 7 = -3x + 12
+ 4x + 4x
   -7 = x + 12
  - 12   -12
-19 = x

The answer is A.

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3 years ago

Write a x (-a)x 13 x a x (-a) x 13 in power notation

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Answer:

$a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Step-by-step explanation:

The given expression

$a\times (-a)\times 13\times a\times (-a)\times 13$

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

$a\times (-a)\times 13\times a\times (-a)\times 13$

= $[13\times13][(a\times (-a)\times a\times (-a)]$

As

$13\times13 = 13^{2}$ , $a\times a = a^{2}$ , $(-a)\times (-a) = (-a)^{2}$

So,

$=[13^{2}][a^2\times (-a)^2]$

As

$(-a)^2 = a^{2}$

So,

$=[13^{2}][a^2\times a^2]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=[13^{2}][a^{2+2}]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=13^{2}\times a^{4}$

$=a^{4}\times 13^{2}$

Therefore, $a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

<em>Keywords: power notation</em>

<em>Learn more about power notation from brainly.com/question/2147364</em>

<em>#learnwithBrainly</em>

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Answer:

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