Answer:
3x > 37
x > 12.333
Thus, 13 and 15 satisfy
Step-by-step explanation:
hope this helps
Answer:
650,000,000 student ID numbers are possible if the letters cannot be repeated.
Step-by-step explanation:
The order in which the digits or letters are placed is important, which means that the permutations formula is used to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:

In this question:
2 letters from a set of 26(permutations, as letters cannot be repeated).
6 digits, each with 10 possible outcomes.
How many student ID numbers are possible if the letters cannot be repeated?

650,000,000 student ID numbers are possible if the letters cannot be repeated.
Answer:
The random variables which has a distribution that can be approximated by a binomial distribution is:
c. The number of students in the sample who scored above average on the SAT.
Step-by-step explanation:
The binomial distribution in this scenario will be between the number of students in the sample who scored below average on the SAT and the number of students who scored above average. Variables that have a binomial distribution must meet these four conditions:
1: The observed number of students who sat for the SAT 'n' is not variable.
2: Each student's score (observation) is purely independent of each other, either above or below average scores.
3: Each student's score (observation) shows one of the two outcomes ("success" or "failure"). Those below average are "failures." Those above average are "successes."
4: The outcome probability of "success" 'p' for each student is the same.
Answer:

Step-by-step explanation:
Turn 2 7/10 to an improper fraction
2 7/10 = 27/10
27/ 10 divided by 1/2 is the same as multiplying 27/10 by the reciprocal of 1/2
27/10 * 2 = 5 2/5
The answer is 
Hope this helps :)
Have a spectacular day!