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DerKrebs [107]
3 years ago
13

One line is y = 3x + 2 and the other line goes through the point (0, -5). Write equation of line.

Mathematics
2 answers:
gladu [14]3 years ago
7 0
I don’t know how u even do this
Lady_Fox [76]3 years ago
3 0

Answer:

y=3x-4 is the slope-intercept form of the equation of a line.  It is in the form y=mx+b.

    m is the slope (often called "rise over run") and b is the y-intercept (the point where x=0).

The y-intercept is the point (0,-4).

We need one other point.  This is where finding easy calculations pays off.  How about where x=2, y=(3)(2)-4 = 2.

That's the point (2,2).

Step-by-step explanation:

tell me if you get it

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a line passes through the point (4 –6) and has a slope of -<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4%7D" id="TexFormu
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Answer:

y = \frac{5}{4}x - 1

Step-by-step explanation:

A line that passes through the point (4,-6) has a slope of 5/-4. Which of the following gives the equation of the line?

With the slope of 5/-4, and the ordered pair (4,-6) :  

let m = 5/-4 (slope),  

x1 = 4

y1 = -6

We can use those given values into the point-slope formula:

y - y1 = m(x - x1)

Plugging in those values will give you the answer:  

y - (-6) = \frac{5}{-4} (x - 4)

Distribute \frac{5}{-4}  into the terms inside the parenthesis:

y + 6 = \frac{ 5}{-4}x  + 5  

  Subtract 6 from both sides to isolate y:

y + 6 - 6 = -\frac{ 5}{4}x +5 - 6

The equation of the line in slope-intercept form is:

y = -\frac{ 5}{4}x - 1  

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