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3 years ago

One line is y = 3x + 2 and the other line goes through the point (0, -5). Write equation of line.

Mathematics

2 answers:

gladu [14]3 years ago

7 0

I don’t know how u even do this

Lady_Fox [76]3 years ago

3 0

Answer:

y=3x-4 is the slope-intercept form of the equation of a line. It is in the form y=mx+b.

m is the slope (often called "rise over run") and b is the y-intercept (the point where x=0).

The y-intercept is the point (0,-4).

We need one other point. This is where finding easy calculations pays off. How about where x=2, y=(3)(2)-4 = 2.

That's the point (2,2).

Step-by-step explanation:

tell me if you get it

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The diagonals of a square are 4 meters long. the side of this square is equal to the diagonal of a second square. find the side

Svetllana [295]

Assume s is the side of the first square.
Let's find out the value of s:
4^2 = 2 × s^2 => s = 2.83 meters

Assume S is the side of the second square. Therefore 2.83^2 = 2 × S^2 => S = 2 meters.

The side of the second square is 2 meters

4 0

3 years ago

Work out 6z - 4z .what is the answer?

Reika [66]

Answer:

4 is the answer

Step-by-step explanation:

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2 years ago

How many 3-digit numbers can you write using only digits 1 and 7? (Of course, digits can repeat.) How many 3-digit numbers can y

Lana71 [14]

Answer:

111,117,177,777,771,711,717,171

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Find (f-g)(x) if f(x)=3x-5 and g(x)=x2-5x+4

solmaris [256]

Answer:

Step-by-step explanation:

Hello,

$(f-g)(x)=f(x)-g(x)=3x-5-(x^2-5x+4)\\\\=3x-5-x^2+5x-4\\\\=-x^2+8x-9$

Thanks

4 0

3 years ago

onyango wishes to fence a rectangular research plot using 100 m of wire .one end of the plot has a wall already erected .calcula

earnstyle [38]

Answer:

1250 m²

Step-by-step explanation:

Let x and y denote the sides of the rectangular research plot.

Thus, area is;

A = xy

Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.

Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;

2x + y = 100

Thus, y = 100 - 2x

Since A = xy

We have; A = x(100 - 2x)

A = 100x - 2x²

At maximum area, dA/dx = 0.thus;

dA/dx = 100 - 4x

-4x + 100 = 0

4x = 100

x = 100/4

x = 25

Let's confirm if it is maximum from d²A/dx²

d²A/dx² = -4. This is less than 0 and thus it's maximum.

Let's plug in 25 for x in the area equation;

A_max = 25(100 - 2(25))

A_max = 1250 m²

5 0

3 years ago