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3 years ago

F(x) = h•g+1 h(x)= 3(x - 1) – 2(2x + 1 g(x)= 8 + 2(x - 1)

Mathematics

1 answer:

Damm [24]3 years ago

3 0

Answer:

g = y - 1/h

h = −x − 5/x

g = 2x + 6/x

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3.If ABCD is a parallelogram with AB = 2x + 1, AD = x + 13, and DC = 3x -11. Determine if ABCD is

madam [21]

Answer:

ABCD is a rhombus

Step-by-step explanation:

Sides AB and DC are opposite and equal in parallelogram ABCD. This means ...

AB = CD

2x +1 = 3x -11

12 = x . . . . . . . . add 11-2x to both sides

Sides AB and CD have length ...

2x +1 = 2(12) +1 = 24 +1 = 25

Then the length of side AD is ...

AD = x +13 = 12 +13 = 25

Adjacent sides AB and AD of the parallelogram have the same length, The figure is a rhombus.

3 0

2 years ago

The diameter of a circle is two times its radius. Which equation shows another way to represent the area of a circle?

Aleksandr [31]

Work shown above! Answer is A = (πD^2)/4. d = diameter
Hope this is what you were looking for!

3 0

3 years ago

Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below.

GaryK [48]

Answer:

Radius length: √5

Standard Form (Equation): (x + 4)^2 + y^2 = 5

Step-by-step explanation:

First we will determine the radius;

Center: (-4, 0)

Point on Circumference: (-2, 1)

d = √(-2 - (-4))^2 + (1 - 0)^2 = √(2)^2 + (1)^2

= √4 + 1 = √5

Therefore the radius is of length √5

Now the equation of a circle is in the form ((x - h)^2 + (y - k)^2) = r^2. The center is in the form (h,k) and r is the radius. Given this our equation would be (x - (-4))^2 + (y - 0)^2 = (√5)^2, or [simplified] (x + 4)^2 + y^2 = 5.

6 0

2 years ago

Read 2 more answers

−3(x + 3) = −3(x + 1) − 5

love history [14]

You have to simplify and then get x

5 0

3 years ago

Read 2 more answers

Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3

Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

$\displaystyle \rho=\frac{m}{V}$

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

$m=\rho.V$

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

$\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3$

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

$\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3$

Calculating:

$V=523.6\ cm^3$

The mass is:

$m=8.09 gr/cm^3 \cdot 523.6\ cm^3$

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0

3 years ago