Answer:
1/4
Step-by-step explanation:
3/12 = 1/4
(We got 12 by adding all the numbers together.)
Answer:
0ft and 60ft
Step-by-step explanation:
Given
The attached function
Required
Determine the valid values of the domain of the function
To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).
From the attached graph, the horizontal distance starts from 0 and ends at 180.
This implies that the domain is: 
From the options, the values that fall in this bracket are 0ft and 60ft
If you divide 21/49 by 7 you get 3/7
There are 10 number of 1 cubic inches box required to fill the container completely.
<h3>What is a cuboid?</h3>
It is defined as the six-faced shape, a type of hexahedron in geometry.
It is a three-dimensional shape.
We have:
A prism with a length of 4 inches, height of 4 inches, and width of 3 inches.
The volume of the prism box = 4×4×3 = 48 cubic inches
Here some data are missing.
We are assuming there are 38 1 cubic inches box already in the big box.
So,
= 48 - 38
= 10
Thus, there are 10 number of 1 cubic inches box required to fill the container completely.
Learn more about the cuboid here:
brainly.com/question/9740924
#SPJ1
Answer:
1595 ft^2
Step-by-step explanation:
The answer is obtained by adding the areas of sectors of several circles.
1. Think of the rope being vertical going up from the corner where it is tied. It goes up along the 10-ft side. Now think of the length of the rope being a radius of a circle, rotate it counterclockwise until it is horizontal and is on top of the bottom 20-ft side. That area is 3/4 of a circle of radius 24.5 ft.
2. With the rope in this position, along the bottom 20-ft side, 4.5 ft of the rope stick out the right side of the barn. That amount if rope allows for a 1/4 circle of 4.5-ft radius on the right side of the barn.
3. With the rope in the position of 1. above, vertical and along the 10-ft left side, 14.5 ft of rope extend past the barn's 10-ft left wall. That extra 14.5 ft of rope are now the radius of a 1/4 circle along the upper 20-ft wall.
The area is the sum of the areas described above in numbers 1., 2., and 3.
total area = area 1 + area 2 + area 3
area of circle = (pi)r^2
total area = 3/4 * (pi)(24.5 ft)^2 + 1/4 * (pi)(4.5 ft)^2 + 1/4 * (pi)(14.5 ft)^2
total area = 1414.31 ft^2 + 15.90 ft^2 + 165.13 ft^2
total area = 1595.34 ft^2
