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3 years ago

HELPPPP

Mathematics

1 answer:

AnnZ [28]3 years ago

4 0

Answer:

130⁰. unsure. angle sum, 25+25+x =180, so x=180-25-25

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The perimeter of a semicircle is 10.28 feet. What is the semicircles radius?

Stels [109]

Answer: the radius is 0.81

4 0

3 years ago

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

7 0

3 years ago

On a piece of paper, use a protractor to construct right triangle DEF with DE=4 in. , m∠D=90° , and m∠E=45° . What statement is

Makovka662 [10]

I think the second one hope this helps

3 0

3 years ago

Evaluating an Expression

Anna35 [415]

Answer:

130

Step-by-step explanation:

18+(4x28)

=18+112

=130

Remember PEMDAS!

5 0

2 years ago

Read 2 more answers

Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require

kotegsom [21]

Answer:

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = $3\frac{2}{3}$ yards

Number of yards required make one ribbon = $\frac{2}{3}$ yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

$a\dfrac{b}{c} = \dfrac{a\times c+b}{c}$

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

$3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}$

One hair bow requires $\frac{2}{3}$ yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

$\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4$

4 hair bows can be made.

4 0

2 years ago