Answer:
the second friend
Step-by-step explanation:
Answer: The bag of candy corn will take 5 seconds to land on the floor and it will hit it with velocity of 49m/s.
Step-by-step explanation: A free falling object has only Gravitational Force acting on it, so acceleration will be due to gravity, which has magnitude
g = 9.8m/s².
As Professor Sosa drops the bag, its initial velocity and time are 0.
The building has a height of 400ft, so adjusting units: y = 121.92 m and
= 0.
For this problem, going down will be the positive reference.
Then:




t ≈ 5
<u>It will take </u><u>5s</u><u> for the candy corn bag to land on the ground.</u>
Acceleration is the change in velocity per change in time, so:

As initial velocity and time are 0 and rearraging it:
v = g.t
v = 9.8*5
v = 49
<u>The bag will hit the ground with </u><u>velocity</u><u> of magnitude </u><u>49 m/s.</u>
Answer:
Perimeter of the quadrilateral PQRS is 25 units
Step-by-step explanation:
From the figure attached,
PQ is a tangent to the given circle so m∠PQR = 90°
Now we apply Pythagoras theorem in the ΔPQR,
PR² = PQ² + QR²
(PT + TR)²= PQ² + 5²
(4 + 5)² = PQ² + 25
81 = PQ² + 25
PQ = √(81 - 25)
= √56
≈ 7.5 units
PQ ≅ PS ≅ 7.5 units
[Since measures of tangents drawn from a point to a circle are always equal]
Perimeter of PQRS = PQ + QR + RS + PS
= 7.5 + 5 + 5 + 7.5
= 25 units
Therefore, perimeter of the quadrilateral PQRS is 25 units.
It is -3, -3
Have a good day