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Yanka [14]
3 years ago
6

Which equation could be used to calculate the cost c for any number of people p to eat at the restaurant

Mathematics
1 answer:
Rudiy273 years ago
8 0

Answer:

The answer is C

Step-by-step explanation:

Because 27.54 divided by 2 = 13.77

each person will be 13.77

if that makes sense

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What is 817x45 in standerd algorithm pls help
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Step-by-step explanation:

  817

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A military aircraft can travel 740 miles per hour. The distance between Tyndall Air Force Base in Florida and Lakenheath Air For
BARSIC [14]

Answer: 3.5 h

Step-by-step explanation:

<u>1. Data:</u>

a) s = 740 miles / h

b) d = 2,567 miles

c) t = ?

<u>2. Equation:</u>

  • speed = distance / time
  • s = d / t

<u>3. Solution:</u>

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        s = d / t ⇒ t = d / s

  • Substitute values:

        t = 2,567 miles / (740 miles/h) ≈ 3.47 h ≈ 3.5 h

   

5 0
3 years ago
Geometry)) Find the value of x
Harlamova29_29 [7]

Answer:

\tt x=14

Step-by-step explanation:

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8 0
2 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
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