8x² - 4 = 28
8x² = 28 + 4
8x² = 32
x² = 32/8
x² = 4
x = <span>±2
</span>
8/ Sine 50 = n/ Sine 90
8 sine 90 = n Sine 50
8 sine 90 / sine 50 = n
n = 10.4
Answer:
First number = 60 and another number = 48
Step-by-step explanation:
Let two numbers are 5x and 4x.
The two number are differ by 12. We need to find the numbers.
ATQ,
5x-4x = 12
x = 12
Now first number = 5x
= 5(12)
= 60
Other number = 4x
= 4(12)
= 48
Hence, the numbers are 60 and 48.
In y = mx + b form, which is what ur equation is in, the y int can be found in the b position
y = mx + b
y = x + 6
as u can see, the number in the b position, ur y int, is 6 <==
Answer: y=x estimate: 88
Step-by-step explanation:
