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3 years ago

Solve it please! -2f - 7(-8f + 3)

Mathematics

2 answers:

amid [387]3 years ago

8 0

I’m pretty sure that should be 54f-21

valentina_108 [34]3 years ago

7 0

Answer:

3(18f−7) (factored)

54f−21 (simplified)

hope this helped :D

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Dora buys one package each of 1lb 2 lb and 4 lb packages of ground beef to make hamburgers. How many 1/4 lb hamburgers can she m

Katarina [22]

1+2+4= 7 lbs. she can make 28 1/4 lb burgers

4 0

3 years ago

Which of the following is the discriminant of the polynomial below x^2+4x+5

steposvetlana [31]

Answer:

$\huge\boxed{\sf Discriminant = -4}$

Step-by-step explanation:

Comparing it with quadratic equation $ax^2 + bx + c = 0$ , we get:

a = 1 . b = 4 and c = 5

So,

Discriminant = $b^2-4ac$

D = (4)²-4(1)(5)

D = 16 - 20

D = -4

Hence,

Discriminant = -4

$\rule[225]{225}{2}$

Hope this helped!

4 0

2 years ago

Find the value of x and the value of y.

kodGreya [7K]

Answer:

6√3 = x y =12

Step-by-step explanation:

Since the two sides of the triangles have equal angles then two sides have equal length

the sum of interior angles of triangles is 180° then the last angle is 60°

then the triangles have perfect sides of 12

y = 12

to calculate x

sin Ф = opposite/hypothenus

sin 60° = x/12

sin 60° = √3/2

( √3/2 ) x 12 = x

6√3 = x

3 0

3 years ago

A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline

dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So $P(B) = 0.35$

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

$P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125$

Probability

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667$

46.67% probability that they flew with airline B.

5 0

3 years ago

Tina is attempting to factor the expression 10x^2-13-3. In her first step, she rewrites the expression as 10x^2-10x-3x-3. Which

Setler79 [48]

ANSWER

B. The two middle coefficients add to the correct number but do not multiply to the correct number.

EXPLANATION

The given quadratic trinomial that Tina tries to factor is

$10 {x}^{2} - 13x - 3$

Comparing to

$a{x}^{2} + bx + c$

we have a=10, b=-13 and c=-3

ac=-3×10=-30

We split the middle term so that their sum is -13.

Tina use

-10,-3

to get

-10x-3x

The sum is -13x alright but the product is not -30.

B is correct.

8 0

3 years ago