Answer:
<h2>total no of markers :36</h2>
in first condition
<h2>no of blue marksers :4</h2>
so probability:
same goes to the second condition
<h2>
<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
First, lets figure out how many pencils we will need. so we can do that by 4 pencils x 28 children and we get 112. Then if there are 8 pencils in a package, we divide 112 by 8 and get 14
Answer:40
Step-by-step explanation:
On a fair die, each face has a 1/6 chance of landing on each toss.
5 and 6 are the only faces greater than 4, therefore there is a 1/6 + 1/6 = 2/6 chance of the die landing on a number greater than 4 for each toss.
Multiply the probability by the total number of tosses to get the number of tosses that are greater than 4.
120 * (2/6) = 240/6 = 40
Approximately 40 tosses will land on a number greater than 4.
