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Ganezh [65]
4 years ago
13

23(9x−6)+4(12x−12) ?

Mathematics
1 answer:
andre [41]4 years ago
5 0

Answer:

47_93/833÷783×881+884=45

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Solve the system of equations 2r + 2s = 50 and 2r – s = 17. A. r = 3, s = 11 B. r = 25, s = 33 C. r = 14, s = 11 D. r = –8, s =
scZoUnD [109]

2r = 17 + s = 50 - 2s \\ 3s = 50 - 17 = 33 \\ s = 11 \\  \\2 r = 50 - 2s \\ 2r = 50 - 2 \times 11 = 50 - 22 = 28 \\ r = 14




C. r=14, s =11
5 0
3 years ago
Needing a answer ASAP! TYYY
dolphi86 [110]

Answer: 840 feet squared

Step-by-step explanation:  24ft * 35ft = 840

4 0
3 years ago
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What is the value of x in the equation (3/4 + 5/8) x = 3/5
mr Goodwill [35]

Answer:

It is x=−92 .

Step-by-step explanation:

3 0
3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
There are 12 big fish for ever 16 small fish. That means that there are____ big fish for every 4 small fish. How many?
Vaselesa [24]

Answer:

3 big fish for every 4 small fish

Step-by-step explanation:

Hope this helps and Happy Holidays!

7 0
3 years ago
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