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belka [17]
4 years ago
12

Isabella has some dimes and some quarters. She has at most 25 coins worth a minimum of $4.45 combined. If Isabella has 17 dimes,

determine all possible values for the number of quarters that she could have.
Mathematics
1 answer:
Rzqust [24]4 years ago
5 0

A is 2

Step-by-step explanation:

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Bobbie wants to make $2.00 using dollars ,half dollars , and quarters.how Many different ways can she make $2.00?
TEA [102]
70. Bobbie wants to make 2.00 dollars using dollars with the value of half dollars and quarters. Now, how many way he can do it? => half dollars = 0.5 => quarter dollars = 0.25 Possible ways: => 0.5 + 0.5 + 0.5 + 0.5 = 2 dollars (4 half dollars) => .25 + .25 + .25 +. 25 + .25 + .25 + .25 + .25 = 2 dollars (8 quarter dollars) => 0.5 + 0.5 + 0.25 + 0.25 + 0.25 + 0.25 = 2 dollars => 0.5 + 0.5 + 0.5 + 0.25 + 0.25 = 2 dollars => 0.5 + 0.25 + .25 + .25 + .25 + .25 + .25 = 2 dollars
3 0
3 years ago
Ashley brought 7/8 gallon of lemonade to the party.
Misha Larkins [42]
<span>7/8 - 2/3 = 5/24 is the correct answer of the question </span>
3 0
3 years ago
Read 2 more answers
What is 0.31 written as a percent?
aalyn [17]
It is 31%.

To explain, you have to just have to multiply 0.31 by 100, and then add a percentage sign.
7 0
3 years ago
Read 2 more answers
At a local track meet, RCMS won 3 blue ribbons than red ribbons. They also won 7 more yellow ribbons than red ribbons. RCMS won
erma4kov [3.2K]
Let no red ribbons=x
no. Of blue ribbons=x+3
No. Of yellow ribb9ns=x+7
Totsl ribbons=28
28=x+x+3+x+7
28=3x+10
3x=28-10
3x=18
X=18/3
X=6

No .of red ribbons=6
No. Of blue ribbons=x+3=9
No. Of yellow ribbons=x+7=13
5 0
3 years ago
The null hypothesis and the alternate hypothesis are: H0: The frequencies are equal. H1: The frequencies are not equal. Category
OLga [1]

Answer:

Reject H0

Step-by-step explanation:

Given :

H0: The frequencies are equal. H1: The frequencies are not equal

Category f0 A 10 B 30 C 30 D 10

Total f0 = (10 + 30 + 30 + 10) = 80

Expected frequency is the same for all categories :

Expected frequency = 1/4 * 80 = 20

χ² = Σ(observed - Expected)² / Expected

χ² = (10-20)^2 / 20 + (30-20)^2 /20 + (30-20)^2 / 20 + (10-20)^2 / 20

χ² = (5 + 5 + 5 + 5) = 20

Pvalue = 0.00017

Pvalue < α

5 0
3 years ago
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