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abruzzese [7]
3 years ago
8

Numbers 6,7,8 I can't figure out

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0
6. Take your compass and place the pointed edge on point B. Place one point on each side of B, each the same distance away from B. Next, place your compass on one of the two new points and extend your compass to draw a circle. Repeat with the SAME radian from the other point. Find where the two circles intersect with each other and draw a line from the points of intersection to point B. Place point A anywhere on that line that you just created and then you're done!

7. Select any place along either line and place point S on it. Next, using the same method as above, draw two circles with the same radius around both points S and R. Draw a line through the intersection points. Locate the intersection where your new line connects with the line across from the shared line of RS. Place a point at the intersection, for your reference, then connect that point to point S. Now you have completed this problem as well.

8. Use a straight edge to draw one line. Place points A and B on each end. Use the circle method yet again to find a line perpendicular to line AB. Next, take your compass and set it to the distance from point A to B. Use that same distance to make a point on the perpendicular line. This creates point C. The final step is to connect A with C and B with C.
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Find the unit rate.<br> 80 rooms on 5 floors<br> =<br> =<br> rooms per floor<br> Submit
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<h3>The formula to find unit rate is:</h3>

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<h2>Now,</h2>

\begin{gathered}\\ \sf\longmapsto \frac{80}{5}\end{gathered}

\begin{gathered}\\ \sf\longmapsto\cancel{\dfrac{80}{5}} \end{gathered}

\begin{gathered}\\ \sf\longmapsto 16\end{gathered}

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The answer to this is

<span> If the lines are the same, the equations are dependent linear equations. Using the graph of y = x and x + 2y = 6, shown below, determine how many solutions the system has. Then classify the system as consistent or inconsistent and the equations as dependent or independent. The lines intersect at one point.</span>


Hope This Helps!
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