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3 years ago

A system of equations has infinitely many solutions. If 2y - 4x = 6 is one of the equations, which could be the other

Mathematics

2 answers:

stira [4]3 years ago

8 0

Answer:

C. –y = –2x – 3

Step-by-step explanation:

edg. unit test

Serjik [45]3 years ago

6 0

Answer:

-y = -2x - 3

Option 3

Step-by-step explanation:

When equations are equivalent, they will have infinitely many solutions.

If you want to find an equivalent equation, you can multiply/divide every term in the equation by the same number. You can also rearrange the equation.

Since the options mostly have "y" by itself, start by rearranging to isolate "y" in the given equation.

Move all the other numbers to the right of the equal sign except for "y". To move a number, apply its reverse operation to the entire equation.

Do reverse operations in reverse BEDMAS order.

2y - 4x = 6 Move "-4x" first. It's reverse is +4x.

2y - 4x + 4x = 6 + 4x

2y = 6 + 4x Move the "2" in 2y. Divide the whole equation by 2.

2y/2 = 6/2 + 4x/2

y = 3 + 2x Rearrange to look like the answer choices.

y = 2x + 3

This equation looks like option 3 except every term has a different negative/positive.

y = 2x + 3 -y = -2x - 3

We can multiply every term by -1.

y = 2x + 3

y*-1 = 2x*-1 + 3*-1

-y = -2x + (-3) Negative and positive make a negative

-y = -2x - 3 Same as option 3

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-10 + 10у + -3y +7 DOES ANYONE KNOW THE ANSWER????????????

Leno4ka [110]

Answer:

The answer is 30.

Step-by-step explanation:

Don't worry about the x and y it just make your head confuse, that's what my teacher said just add up the number.

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2 years ago

Find the coordinates of the midpoint of (x,y) for A(9,1) and B(3,7)

tekilochka [14]

9514 1404 393

Answer:

(6, 4)

Step-by-step explanation:

The midpoint is found as the average of the coordinates of the end points.

M = (A +B)/2

M = ((9, 1) +(3, 7))/2 = (9+3, 1+7)/2 = (12, 8)/2

M = (6, 4)

The midpoint of segment AB is (x, y) = (6, 4).

5 0

3 years ago

Two dice are tossed. The probability that the total score is a prime number is:

andrew11 [14]

Step-by-step explanation:

50/50 it's random I think but I learned that in science

8 0

3 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago

Paul lands a home mortgage of $58,200 at a

qwelly [4]

Answer:

$72,100

Step-by-step explanation:

To calculate the total principal+interest payment, you can use the formula to find the future value:

FV=PV(1+i)^n

FV= Future value

PV= Present value= $58,200

i= Interest rate= 7.40%

n= Number of periods of time= 3 years

Now, you can replace the values on the formula:

FV=58,200*(1+0.0740)^3

FV=58,200*(1.0740)^3

FV=72,100

According to this, the answer is that the total principal + interest payment will be $72,100.

8 0

2 years ago