Answer:
land on 3: 36 times
land on 4: 63 times
Step-by-step explanation:
A biased dice is the opposite of a fair dice.
A fair dice has the same probability of landing any of the six numbers: 1/6
The biased dice has different probabilities for its results.
To solve this question, first we need to find the probability of landing a 3.
The sum of all probabilities need to be 1, so:
0.13 + 0.05 + p(3) + 0.21 + 0.19 + 0.3 = 1
p(3) = 1 - 0.88 = 0.12
If we roll the dice 300 times, the expected number of times the dice will land:
on 3: 300 * p(3) = 300 * 0.12 = 36 times
on 4: 300 * p(4) = 300 * 0.21 = 63 times
Answer:
according to theorm 8 of basic geometry the answer is 6
I dont understand your question.......
Step-by-step explanation:
can't really use the Pythagorean because you don't know this is a right triangle.
use the fact that they are similar
so
3/6 = x/12 where x is FE
cross multiply
6x = 36 therefore FE = 6
then 6/12 = y/9 where y is FD
cross multiply
12y = 54 = 54/12 therefore FD = 4.5
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
