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nordsb [41]
3 years ago
9

Write a sentence to compare the two points shown on the number line -2.7 and 4.5

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0
4.5 has a greater value than -2.7.
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The sum of the angle measures of a triangle is 180°. Find the value of x . Then find the angle measures of the triangle.
Lady bird [3.3K]

Answer:

Step-by-step explanation:

The sum of the angle measures of a triangle is 180°. Find the value of x . Then find the angle measures of the triangle.

find the value of x

x + 2x + x + 8 = 180

4x = 180 - 8

4x = 172

x = 172 : 4

x = 43

find angles

2x = 43 * 2

2x = 86°

-------

x = 43°

--------

x + 8 = 43 + 8

x = 51°

-----------------------

check

86 + 43 + 51 = 180°

the answer is good

6 0
2 years ago
Jack cuts a pie into 4 equal parts. The pieces are called _______ of the pie​
djyliett [7]
Fractions of the pie?
7 0
3 years ago
Read 2 more answers
En la expresion algebraica x², ¿que indica el número 2 en la base x?
tino4ka555 [31]

Answer:

En la expresión, 2 representa la cantidad de veces que multiplicas x por sí mismo.

**Lo siento si mi español es malo, el inglés es mi primer idioma.

Step-by-step explanation:

8^{2} = 8 × 8 = 64

y^2= y × y

5 0
3 years ago
Find an angle between 0° and 360° that is coterminal with the given angle
mezya [45]
Add or subtract 360 degrees to find a coterminous angle. Since the questions wants you to find one between 0-360, you should subtract 360.
453-360=93 degrees
5 0
3 years ago
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
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