3 years ago

What is the volume of a cylinder with the following dimensions Radius 6ft Height 24ft

1 answer:

OLga [1]3 years ago

4 0

V≈2714.34ft³I hope this answer your question.

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Oliga [24]

1/3 is the same as 3/9. To solve this, subtract 3/9 from 7/9.

$\frac{7}{9}-\frac{3}{9}= \frac{4}{9}$

Your answer is $\frac{4}{9}$

4 0

3 years ago

murzikaleks [220]

Given

$y=x^2-6x+8$

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

$y^{\prime}=2x-6$

Equating

$y^{\prime}\text{ = 0}$

gives the minimum value we require.

Doing that, we have:

$2x-6=0$

So that

$\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}$

Therefore, the minimum value is x = 3

8 0

1 year ago

Ivan

I think is 1863 m because if you use the formula for area

8 0

3 years ago

goldfiish [28.3K]

x=-26 is the final anwser :)

5 0

2 years ago

dybincka [34]

Answer:

41 if I'm reading the question right.

3 0

3 years ago