Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Answer:
Its 52/69... did u mean 69 divide by 52? If so the answer is 69/52.
Step-by-step explanation:
Hopefully u wrote the answer correctly, as always plz mark as brainliest. Hope this helps!
Oh wait!
The decimal form is: 0.753621 i think
Y intercept is negative 8
Answer:
7
Step-by-step explanation: 6 + 5 + 8 + 5 + 9 + 6 + 7 + 5 + 12 = 63 so now u just divide that by 9
7844=7400(1+(8/12)r)
Solve for r
R=0.09*100=9%
