Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Based on the statement below, if d is the midpoint of the segment AC, the length of the segment AB is 4.5cm.
<h3>What is the line segment about?</h3>
in the question given,
AC = 3cm,
Therefore, AD and DC will be = 1.5cm segments each.
We are given C as the midpoint of segment DB.
So CB = 1.5cm.
The representation of the line segment is:
A-----------D------------C-------------B
1.5 1.5 1.5
Since AD, DC and CB are each 1.5cm segments. Then the equation will be:
= 1.5 + 1.5 + 1.5
= 4.5
Therefore, The length of the segment AB is 4.5cm.
See full question below
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm.
Learn more about midpoint from
brainly.com/question/10100714
#SPJ1
Answer:
-10
Step-by-step explanation:
First use this equation: (y2 - y1) / (x2 -x1)
The y intercept is 14 so the slope is -10.
Answer:
75%
Step-by-step explanation:
Answer: the answer is
Step-by-step explanation:
