Answer:
Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.
Step-by-step explanation:
Given , Josiah owns a food truck that sells tacos and burritos.
He sells each burritos for $7.50. If 79 burritos were sold.
Then the price of 79 burritos is $(7.50×79) =$592.50
Let x tacos were sold.
He sells each tacos for $5.
Then the price of x tacos is = $(x × 5)=$5x
Also given that Josiah must sell a minimum of $930 worth of tacos and burritos.
Therefore,
5x+592.50≥ 930
⇔5x≥930-592.50
⇔5x≥337.5
⇔x≥67.5
But he only has enough supplies to make 149 tacos or burrito.
He already sold 79 burrito.
So, remain space for tacos is = (149-79) = 70
So,67.5≤x≤70
∴x = 68 or 69 or 70
Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.
Answer:
the cup will land on its side 310 times and it'll land on the end 55 times
Step-by-step explanation:
To determine the amount of times it lands on the side, take the days in a year, 365, and multiply that by .85, which gets you 310. To get the amount of times it lands on its end, just subtract 310 from 365.
Answer: 9 7/8
Step-by-step explanation:
1. you take 237/24 and simplify = 79/8
2. you take 79/8 and make it into a mixed number = 9 7/8
