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svetoff [14.1K]
3 years ago
11

What is the quotient of 15,048 and 76​

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

If you mean 15,048 ÷ 76, the quotient is 198.

If you mean 76 ÷ 15,048, the answer is 0.00505050505. But I doubt that’s what you mean.

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Is ∆JKL ≅ ∆KJM ? Justify your answer below.
makkiz [27]

Answer:

Yes, the triangles are congruent by ASA

Step-by-step explanation:

we know that

If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)

In this problem

LK=MJ

∠KLJ=∠KMJ

∠LKJ=∠MJK

so

Two angles and the included side is equal in triangle JKL and triangle KJM

therefore

JKL≅KJM ----> by ASA

4 0
3 years ago
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How do you do fraction ,like 20 on top line then 30 on bottom ,I was bad art math sorry please explaine to my daughter so she ca
telo118 [61]
Alright, so since I don't have an example question, I will make one up. 

there are 8 coins in total. there are 6 dimes. What is the fraction of dimes to coins. 

you would put the amount of dimes on the top and the total on the bottom.

Answer: 6/8 which can be simplified to 3/4

Or another Example:

There are 12 pieces in the pizza. Billy took 4. what is the fraction of the slices left.

it would be 4-12= 8

Answer: 8/12 which can be simplified to 4/6 and then to 2/3

Hope that helped.
8 0
2 years ago
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What is the circumference of a circle with a diameter of 5 feet? use 3.14 for pi
artcher [175]

Answer:

15.7

Step-by-step explanation:

Circumference= πd

d= Diameter

7 0
3 years ago
Write an equation in slope-intercept form of the line that passes through (6, -1) and (3, 47)
katrin2010 [14]

Answer:

Step-by-step explanation:

(47+1)/(3-6) = 48/-3 = -16

y + 1 = -16(x - 6)

y + 1 = -16x + 96

y = -16x + 95

6 0
3 years ago
A solid oblique pyramid has a square base with edges measuring x cm. The height of the pyramid is (x + 2) cm. Which expression r
zavuch27 [327]

we know that

the volume of a solid oblique pyramid is equal to

V=\frac{1}{3}*B*h

where

B is the area of the base

h is the height of the pyramid

in this problem we have that

B is a square

B=b^{2}

where

<u>b=x\ cm</u>

so

B=x^{2}\ cm^{2}

h=(x+2)\ cm

substitute in the formula of volume

V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

therefore

<u>the answer is</u>

V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

4 0
2 years ago
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