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Oduvanchick [21]
4 years ago
14

A substance called _____ contains the instructions for life.

Biology
1 answer:
salantis [7]4 years ago
4 0
<span>DNA is the substance within every living cell that contains the instructions for life.</span>
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Scientists often perform repeated investigations. What is the main reason for this.
VLD [36.1K]
That way they can get the average result and they're usually more accurate.
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3 years ago
10. Define the following terms:<br>a. Nucleoid-<br>b. Mesosomes -<br>d. Capsid -<br>e. Plasmalemma-​
malfutka [58]

Answer:

Alright, sure thing.

Explanation:

a. Nucleoid- The nucleoid (meaning nucleus-like) is an irregularly-shaped region within the cell of a prokaryote that contains all or most of the genetic material.

b. Mesosomes- Mesosomes or chondrioids are folded invaginations in the plasma membrane of bacteria that are produced by the chemical fixation techniques used to prepare samples for electron microscopy.

d. Capsid- A capsid is the protein shell of a virus, enclosing its genetic material.

e. Plasmalemma-​ The cell membrane is a biological membrane that separates the interior of all cells from the outside environment which protects the cell from its environment.

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Read 2 more answers
Complete the given statement with the most appropriate words.
aliya0001 [1]
Answer #1: instinctual trait
Answer#2: learned trait
6 0
3 years ago
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aev [14]
The second one is the answer
6 0
3 years ago
Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the pro
Anit [1.1K]

Answer:

3/4

Explanation:

If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.

<h3><u>Gene A</u></h3>

AA x Aa

  • F1 genotypes: 1/2 AA, 1/2 Aa
  • F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>

BB x bb

  • F1 genotypes: 1 Bb
  • F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>

Cc x Cc

  • F1 genotypes:  1/4 CC, 2/4 Cc, 1/4 cc
  • F1 phenotypes: 3/4 C, 1/4 cc

We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:

<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
6 0
3 years ago
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