5. Find the actual distance between two cities that are 4 3/4 inches apart on a map with a scale of 1 inch per 40 miles

the expression 5n can be. used to find the total cost in dollars of bowling where n is the number of games bowled and 2 represen

sergiy2304 [10]

17 dollars for Vincent to bowl 3 gamees

4 0

3 years ago

Read 2 more answers

Based on a survey, that 46% of consumers are comfortable having drones deliver their purchases. Suppose that we want to find the

Wewaii [24]

$n=5,x=3,p=0.46,q=0.54$ .

<u>Step-by-step explanation:</u>

Here we have , Based on a survey, that 46% of consumers are comfortable having drones deliver their purchases. Suppose that we want to find the probability that when five consumers are randomly selected, exactly three on them are comfortable with delivery by drones. We need to find the values of n,x,p,and q .Let's find out:

According to question , 46% of consumers are comfortable having drones deliver their purchases , So , Probability of success :

⇒ $p=0.46$

And , probability of failure :

⇒ $q=1-p =1-0.46$

⇒ $q=0.54$

Now , n = Number of people randomly selected = 5

x = Number of people exactly comfortable = 3

Therefore , $n=5,x=3,p=0.46,q=0.54$ .

4 0

3 years ago

You and 4 friends are starting a business selling bagels. The 5 of you open a bank account strictly for the business. You would

Norma-Jean [14]

Answer:

each 25 dollars :))))))

3 0

3 years ago

SOLVE 3 AND 4 I WILL GIVE BRAINLIST!!

ZanzabumX [31]

Answer:

3. C≈31.42

4.C≈94.25

Step-by-step explanation:

10 ÷ 2 =5

C=2πr

c=2 (3.14) 5

c= 2(3.14)15

7 0

3 years ago

Resolve into partial fractions 7-5x/2x^2+x-1

Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\$

To find:

partial fractions=?

Solution:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\$

putting $x=-1$

$\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\$

putting $x= \frac{1}{2}$

$\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2} \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\$

So, the final answer is " $\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\$ ".

Learn more:

brainly.com/question/22286068

3 0

3 years ago