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2 years ago

How many hundreds are in 1,000

Mathematics

2 answers:

Rom4ik [11]2 years ago

5 0

There are 10 hundreds in 1000

krek1111 [17]2 years ago

4 0

There are 10 hundreds in 1,000 because 100 x 10 = 1,000

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What is BC of the prism

REY [17]

It is the lateral edge as it is an edge and it is on the lateral area.

4 0

2 years ago

What is the value of X that makes equation true? -5(2x - 3) + 4x = -3x + 6

Alisiya [41]

Answer:

x=3

Step-by-step explanation:

6 0

2 years ago

HELP!!!!!!!!!!!

Svetradugi [14.3K]

Using the mean concept, it is found that:

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

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The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.

In this problem:

The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}

5 observations.

Thus, the mean is:

$M = \frac{1.25 - 1 + 2.25 + 0 - 2}{5} = 0.1$

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

A similar problem is given at brainly.com/question/24787716

7 0

2 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago

Help fast please due soon

vaieri [72.5K]

#1 m=7/4 the whole equation would be y=7/4x + 3/2

8 0

2 years ago