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choli [55]
3 years ago
12

What did each of the seven frogs weight

Mathematics
2 answers:
Studentka2010 [4]3 years ago
5 0
Plz provide more info and repost.
puteri [66]3 years ago
3 0
Where is the picture
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Find the values of k and b if it is known that the graph of y=kx+b goes through points (2, 10) and (−7, −10).Plz help i dont get
zimovet [89]

k = \frac{20}{9} and b = \frac{50}{9}

Given 2 points that lie on the graph of y = kx + b then the coordinates of these points will make the equation true. Substituting the coordinates into the equation allows us to find k and b

(2, 10) → 10 = 2k + b → (1)

( - 7, - 10) → - 10 = - 7k + b → (2)

subtracting (2) from (1) term by term gives

(10 - (- 10)) = (2k - (- 7k)) + (b - b)

20 = 9k → ( divide both sides by 9)

k = \frac{20}{9}

Substitute this value into ( 1) or (2) and solve for b

(1) → 10 = (2 × \frac{20}{9}) + b

hence b = \frac{90}{9} - \frac{40}{9} = \frac{50}{9}


8 0
3 years ago
Factorise x squared-x
yKpoI14uk [10]

Answer:

x^2 - x

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Step-by-step explanation:

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3 years ago
Find the product.<br>(-3) (8)​
wolverine [178]

-3\cdot8=\underline{-24}

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Each paper clip is 3/4 of an inch long and costs $.02. Exactly enough paper clips are laid end to end to have a total length of
AlexFokin [52]
So,
3/4=0.75
36/0.75=48
You need 48 paperclips to make it end to end.
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Hope I helped!
3 0
3 years ago
Two cards are drawn from a standard 52-card deck, without replacement. Find the probability that they are both aces.
Delvig [45]
4 aces in a deck = 4/52 = 1/13
then <span>without replacement, 3 aces in 51 cards
so
</span>1/13 * 3/51
= 3/663
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answer
<span>C.
1/221</span>
6 0
3 years ago
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