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Vinvika [58]
3 years ago
11

Each paper clip is 3/4 of an inch long and costs $.02. Exactly enough paper clips are laid end to end to have a total length of

36 inches. What is the total cost of these paper clips?
Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0
So,
3/4=0.75
36/0.75=48
You need 48 paperclips to make it end to end.
The cost is:
48 x 0.02=0.96
The total cost is $0.96

Hope I helped!
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If 2×2=4 and 4×4=8. What is 8×8?​
Oxana [17]

Answer:

64

Step-by-step explanation:

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2 years ago
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FedEx will ship the Olympic medals from the producer to Japan. Each medal weighs 0.5 kilograms. A box carries 6 medals. If FedEx
kherson [118]

Answer:

42

Step-by-step explanation:

weight of medals:

30 (0,5) = 15 kg

cost of 5 kg:

28/2 = 14

cost of shipping:

14+28=42

6 0
2 years ago
Write an equation of the circle with center (-7,4) and radius 11.
olga_2 [115]

Answer: (x+7)^2 + (y-4)^2 = 121  or  (x+7)^2 + (y-4)^2 = 11^2

Step-by-step explanation:

Equation of the circle is:

(x-h)^2+(y-k)^2=r^2 , which is the center (h,k) and the radius r^2

-Place the center (-7,4) and radius 11 onto that equation:

(x+7)^2+(y-4)^2=121 (if simplified radius needed)

or

(x+7)^2(y-4)^2=11^2

7 0
3 years ago
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Which of the following statements is not true about the function shown above?
Studentka2010 [4]
Answer A would the one that's false
8 0
3 years ago
A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v
BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

p_{1}=\frac{30}{120}=0.25

p_{2}=\frac{32}{160}=0.2

Second, calculate standard deviation for each proportion:

\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395

\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316

Now, we calculate standard error for difference:

SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}

SE=\sqrt{0.0395^{2}+0.0316^{2}}

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

p_{1}-p_{2} ± z-score.SE

0.25-0.2 ± 1.645(0.0505)

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = -0.0332

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is [-0.0332,0.1332].

8 0
3 years ago
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