I think it would be 363.21 because you are moving the digits down by 10
F(3): 6-3(3)=6-9=-3
f(-3): 6-3(-3)=6-(-9)=6+9=15
-3+15=12
Answer:
-3
The problem:
The sum of four consecutive integers is - 18. What is the greatest of these
integers?
Step-by-step explanation:
If n is the first integer, then n+1 is the second integer, n+2 is the third integer, and n+3 is the fourth integer in consecutive order.
For example if n=8, we are saying n+1=9,n+2=10, and n+3=11, which I think you can see that 8,9,10,11 are consecutive.
So the sum is -18 which means:
n+(n+1)+(n+2)+(n+3)=-18
4n+6=-18
Subtract 6 on both sides:
4n=-18-6
Simplify:
4n=-24
Divide both sides by 4:
n=-6
If n=-6,
then:
n+1=-6+1=-5
n+2=-6+2=-4
n+3=-6+3=-3.
So the 4 consecutive integers whose sum is -18 is: -6,-5,-4, and -3.
The greatest of these integers is -3.
At first they bought 40 uniforms for $3,000. When divided, the result came out as 75$ per each uniform. If they only received 40$ back then, 70-40=30. So the difference was 30$ per uniform.
The sum of the three interior angles would be 180°
Hope this helped
