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amm1812
3 years ago
10

How to solve for x in the equation a 3x=x/2?

Mathematics
1 answer:
aalyn [17]3 years ago
8 0
3x = x / 2

Mmc (2,1) = 2

6x = x
6x- x = 0
5x= 0
x = 0/5
x = 0


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Solve for S 12s = 72
ryzh [129]

Answer:

s=6

Step-by-step explanation:

72/12=6 simplify both sides

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Suppose x = 5 is a solution to the equation 4x − 3(x + a) = 2. Find the value of a that makes the equation true. Group of answer
xz_007 [3.2K]
Just replace all of the x’s with 5 and solve using order of operations. I will post what I got for my answer in the comments of the answer if you need it.
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Instructions: Find the lengths of the other two sides of the isosceles right triangle below.
Alexandra [31]

Given:

The ratio of 45-45-90 triangle is x:x:x\sqrt{2}.

The hypotenuse of the given isosceles right triangle is 7\sqrt{2}.

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The lengths of the other two sides of the given isosceles right triangle.

Solution:

Let l be the lengths of the other two sides of the given isosceles right triangle.

From the given information if is clear that he ratio of equal side and hypotenuse is x:x\sqrt{2}. So,

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6 0
3 years ago
The quotient of two numbers is 4, and the difference is 3. What are the two numbers
Pie

Answer:

The numbers are 4 and 1

Step-by-step explanation:

Let x and y be the numbers

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x/y = 4

x-y =3

Taking the first equation and multiplying each side by y

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6 0
3 years ago
Click once to choose an answer. Click again to change your answer. Choose all that locate the ordered pair in the correct quadra
forsale [732]

Answer:

Quadrant\ IV = (5, -3)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Step-by-step explanation:

Given

Quadrant\ IV = (5, -3)

Quadrant\ II  = (-4, -8)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Required

Determine which coordinate fall in the right quadrant

First, we split the each quadrant into x and y axis

In the first:

x and y is +

In the second:

x is - and y is +

In the third

x and y are -

In the fourth

x is + and y is -

Comparing the given coordinates to their respective quadrants, base on the conditions stated above

Quadrant\ IV = (5, -3)  is correct

Quadrant\ I = (9, 11) is correct

Quadrant\ II = (-1, 3) is correct

Quadrant\ III = (-2, -4) is correct

Quadrant\ II  = (-4, -8) is incorrect

3 0
3 years ago
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