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amm1812
3 years ago
10

How to solve for x in the equation a 3x=x/2?

Mathematics
1 answer:
aalyn [17]3 years ago
8 0
3x = x / 2

Mmc (2,1) = 2

6x = x
6x- x = 0
5x= 0
x = 0/5
x = 0


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What is 22/9 as a mixed number
sergiy2304 [10]
If you do 22÷9 and see the hole number: 2. Then do 2 x 9 and you get 18. Now do 22-18 and you get 4. So do 2 4/9. Always have the denominator stay the same.
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Find the area of this trapezoid. Be sure to include the correct unit in your answer.
melisa1 [442]

Answer:

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3 years ago
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Pls help picture provided
Zanzabum

Answer: second option

Step-by-step explanation:

The standard form of a quadratic equation is:

ax^2+bx+c=0

Then, to write the quadratic equation given in the problem in standard form, you must substract 1 from both sides of the equation. Then you have:

2x^2+5x-1=0

Given the quadratic equation above, to find the value of b^2-4ac  you must substitute:

a=2; b=5 and c=-1 into b^2-4ac

Thenrefore, you obtain the following result:

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8 0
3 years ago
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NEED HELP ! 20 POINTS
prohojiy [21]

If z=1-i, then |z|=\sqrt{1^2+(-1)^2}=\sqrt2 and \arg z=-\dfrac\pi4 because z lies in the fourth quadrant.

By DeMoivre's theorem,

z=|z|e^{i\arg z}\implies z^{10}=(\sqrt2)^{10}e^{-i10\pi/4}=32e^{-i5\pi/2}=32e^{-i\pi/2}=-32i

so the answer is B.

8 0
3 years ago
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