Question

Pls help picture provided

Answer 1

Answer: second option

Step-by-step explanation:

The standard form of a quadratic equation is:

$ax^2+bx+c=0$

Then, to write the quadratic equation given in the problem in standard form, you must substract 1 from both sides of the equation. Then you have:

$2x^2+5x-1=0$

Given the quadratic equation above, to find the value of $b^2-4ac$  you must substitute:

a=2; b=5 and c=-1 into $b^2-4ac$

Thenrefore, you obtain the following result:

$5^2-4(2)(-1)=33$

Answer 2

Answer:

$33$

Step-by-step explanation:

The given quadratic equation is

$1=2x^2+5x$

We want to rewrite this equation in the form;

$ax^2+bx+c=0$

We add $-1$ to both sides of the equation to obtain;

$0=2x^2+5x-1$

This is the same as

$2x^2+5x-1=0$

This implies that;

$a=2,b=5,c=-1$

We substitute these values into the expression $b^2-4ac$

$\Rightarrow 5^{2}-4(2)(-1)$

$=25+8$

$=33$