2 years ago

How do you solve a SSA triangle?

1 answer:

5 0

Since sin(100)/5 is equivalent to sinA/9, then:
$sinA = \frac{9sin(100)}{5}$
$A = sin^{-1}(\frac{9sin(100)}{5}$

Type that into your calc to find A.

Repeat this process with C.

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The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

2 years ago

Read 2 more answers

Complete the table to describe the model. The model will have a verbal description, a division expression, and a fraction.

NARA [144]

Answer:

what I dont even know whT your talking about. could you please explain your question a bit more?? then maybe I could help you out

5 0

2 years ago

What is the distance between (-5,8) and (4,6)

nika2105 [10]

Answer: