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Hatshy [7]
2 years ago
6

How do you solve a SSA triangle?

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
5 0
Since sin(100)/5 is equivalent to sinA/9, then:
sinA = \frac{9sin(100)}{5}
A = sin^{-1}(\frac{9sin(100)}{5}

Type that into your calc to find A.

Repeat this process with C.
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djyliett [7]
I think it’s 128 or 64
5 0
2 years ago
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PLEASE I NEED HELP, ILY ILL GIVE 30 POINTS
Novosadov [1.4K]

Answer:

Question 1:

The angles are presented here using Autocad desktop application

The two column proof is given as follows;

Statement                   {}                             Reason

S1. Line m is parallel to line n       {}            R1. Given

S2. ∠1 ≅ ∠2                   {}                            R2. Vertically opposite angles

S3. m∠1 ≅ m∠2                    {}                     R3. Definition of congruency

S4. ∠2 and ∠3 form a linear pear      {}      R4. Definition of a linear pair

S5. ∠2 is supplementary to ∠3 {}      R5. Linear pair angles are supplementary

S6. m∠2 + m∠3 = 180°              {}                Definition of supplementary angles

S7. m∠1 + m∠3 = 180°              {}                 Substitution Property of Equality  

S8. ∠1 is supplementary to ∠3           {}      Definition of supplementary angles

Question 2:

(a) The property of a square that is also a property of a rectangle is that all the interior angles of both a square and a rectangle equal

(b) The property of a square that is not necessarily a property of all rectangles is that the sides of a square are all equal, while only the length of the opposite sides of a rectangle are equal

(c) The property of a rhombi that is also a property of a square is that all the sides of a rhombi are equal

(d) A property of a rhombi that is not necessarily a property of all parallelogram is that the diagonals of a rhombi are perpendicular

(e) A property that applies to all parallelogram is that the opposite sides of all parallelogram are equal

Step-by-step explanation:

7 0
3 years ago
Please answer one question asap <br>A(-4,3) B(2,-1) D(-4,-1) C(2,-5)
Leni [432]

Answer:

Step-by-step explanation:

Vertices of the given quadrilateral are A(-4, 3), B(2, -1), C(2, -5) and D(-4, -1)

Since, slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope of AB = \frac{3+1}{-4-2}

                    = -\frac{2}{3}

Slope of AD = \frac{3+1}{-4+4}

                    = Not defined (Parallel to y-axis)

Slope of DC = \frac{-5+1}{2+4}

                     = -\frac{2}{3}

Slope of BC = \frac{-1+5}{2-2}

                   = Not defined (Parallel to y-axis)

Slope of AB = slope of DC = -\frac{2}{3}

Slope of BC = slope of AD = Not defined (parallel to y-axis)

As per property of a parallelogram,

"Opposite sides of a parallelogram are parallel and equal in measure"                  

Therefore, ABCD is a parallelogram.

8 0
3 years ago
Please help I have 15 minutes!!!!!
Ber [7]

Answer:

false

Step-by-step explanation:

Plug in the numbers given by the then statements. Plugging in -2 for x gives us -3 >= 3 which is false.

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3 years ago
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evablogger [386]
The top angle inside the triangle would be 90-20 = 70 degrees

 so X = 15 / tan(7) = 5.45 = 5.5 yd

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3 years ago
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