What is the value of n. n=3 x 45

PLEASE HELP ME!! I can’t figure this out

DochEvi [55]

Hello!

The problem has asked that we write a point-slope equation of the line in the image above. Point-Slope Form uses the following formula:

y – $y_{1}$ = m(x – $x_{1}$ )

In this case, M represents the slope while $X_{1}$ and $Y_{1}$ represent the corresponding X and Y values of any given point on the line.

We are given that the slope of the line is - $\frac{5}{7}$ . We also know that any given point on a graph takes the form (x,y). Based on the single point provided in the image above, we can determine that $X_{1}$ is equal to 6 and $Y_{1}$ is equal to 2. Now insert all known values into the point-slope formula above:

y – 2 = - $\frac{5}{7}$ (x – 6)

We have now successfully created an equation based on the information given in the problem above. Looking at the four possible options, we can now come to the conclusion that the answer is C.

I hope this helps!

7 0

3 years ago

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel

Andre45 [30]

Answer:

Step-by-step explanation:

Given

there are six integers to win a lottery

case-1 Integer not exceeding 40

no of ways to choose 6 incorrect numbers

$=\dfrac{^{34}C_{6}}{^{40}C_{6}}$

$=0.35$

Case-2 no of ways to choose 6 incorrect numbers out of 48 integers

$=\dfrac{^{42}C_{6}}{^{48}C_{6}}$

$=0.427$

Case-3 no of ways to choose 6 incorrect numbers out of 56 integers

$\dfrac{^{50}C_{6}}{^{56}C_{6}}$

$=0.489$

Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers

$\dfrac{^{58}C_{6}}{^{64}C_{6}}$

$=0.54$

6 0

3 years ago

A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the

Kay [80]

Answer: The required number of quarters in the collection is 11.

Step-by-step explanation: Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05, 1 dime = $ 0.10 and 1 quarter = $0.25.

Then, according to the given information, we have

$x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

$(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)$

and

$y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Comparing the values of y from equations (iv) and (v), we get

$47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.$

Thus, the required number of quarters in the collection is 11.

7 0

3 years ago

An electronics store makes a profit of $72 for every television sold and $90 for every computer sold. The manager’s target is to

exis [7]

the complete question in the attached figure

we have

$72 ------------------------------------ > for every television sold

$90 ------------------------------------ > for every computer sold.

let

x--------------------- > numbers of television sold

y--------------------- > numbers of computer sold

then

72x+90y >= $360 ----------- >72x/72+90y/72 >= $360 /72---- >x+1.25y >= $5

y >= (5-x)/1.25--------------see the graph in attached figure

case A---------- > (5,2) (3,3) (1,4)

72x+90y --------- > 72*5+90*2=540 >= 360----- > is solution

72x+90y --------- > 72*3+90*3=486 >= 360----- > is solution

72x+90y --------- > 72*1+90*4=432 >= 360----- > is solution

case B------------ > (4,0) (2,2) (1,1)

72x+90y --------- > 72*4+90*0=288 < 360----- > is not solution

72x+90y --------- > 72*2+90*2=324 < 360----- > is not solution

72x+90y --------- > 72*1+90*1=162 < 360----- > is not solution

case C------------ > (3,1) (2,2) (1,0)

72x+90y --------- > 72*3+90*1=306 < 360----- > is not solution

72x+90y --------- > 72*2+90*2=324 < 360----- > is not solution

72x+90y --------- > 72*1+90*0=72 < 360----- > is not solution

case D------------ > (4,0) (3,3) (1,4)

72x+90y --------- > 72*4+90*0=288 < 360----- > is not solution

72x+90y --------- > 72*3+90*3=486 >= 360----- > is solution

72x+90y --------- > 72*1+90*4=432 >= 360----- > is solution

<span>the answer is case A </span>

4 0

4 years ago

Read 2 more answers

in a 10 team league, each teams play every other team exactly twice. find the total number of games played in the league

LuckyWell [14K]

Since it’s a 10 team league and each team plays with the other team twice then 10+10=20, thus there would be 20 games played

7 0

3 years ago