The temperature in Montreal was -8°C
2 answers:
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Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus
solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus
solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2
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I just gave you 0.888 is it's fraction and percentage.
First, 111/125 is the simplified answer and is over the 100th and is not big enough for the 1,000's.
Second, 111/125 as a percentage is 88.8%.
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