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3 years ago

The temperature in Montreal was -8°C

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

6 0

Answer:

Temperature was 19 degree warmer in New York compare to temperature in Montreal.

Solution:

Given information is as follows

Temperature in Montreal = -8

Temperature in New York = 11

Need to find by how much degree the temperature was warmer in New York.

degree by which temperature was warmer in New York compared to Temperature of Montreal is equal to (Temperature in New York) – (Temperature in Montreal)

= 11 – (-8) = 11 + 8 = 19

Hence temperature was 19 degree warmer in New York compare to temperature in Montreal.

atroni [7]3 years ago

5 0

Answer:

id say about 19 degrees

Step-by-step explanation:

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Nastasia [14]

Answer:

The median is -8°F

Step-by-step explanation:

Attached Table.

The median is the "middle" value from all the numbers arranged from least to greatest.

Looking at the table, we need to arrange the numbers (first week numbers) from least to greatest.

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There are 7 numbers and the middle number is the 4th one, which is -8

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3 years ago

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Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
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sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
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sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
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tan(\theta)=\cfrac{opposite}{adjacent}\\\\
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$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
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sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
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\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
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c=hypotenuse\\
a=adjacent\\
b=opposite\\
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$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
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\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
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tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
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\textit{and now, let's rationalize the denominator}
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\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
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3 years ago

The solution set for the equation x - 6x + 10 = 0 is

Oxana [17]

Answer:

{3-i, 3+ i}

Step-by-step explanation:

hello : the equation is : x²-6x+10 =0

because : (3+i)²-6(3+i)+10 = 9+6i+i²-18-6i+10 =9+6i-1-18-6i+10 =0...right

same method for 3-i... (all quadratic equation have two conjugate solution)

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3 years ago

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Kobotan [32]

There are 99 miles left. 43(7)=301. 400-301=99.

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3 years ago

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4/11x10/8 What is the answer

aliya0001 [1]

Answer:

5/11

Step-by-step explanation:

4/11 × 10/8

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3 years ago