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In-s [12.5K]
3 years ago
12

By decreasing each dimension by 2 units units​, the area of a rectangle decrease from 48 square feet​ (on the​ left) to 24 squar

e feet​ (on the​ right). find the percent decrease in area.
Mathematics
1 answer:
Ket [755]3 years ago
8 0
The original area is <span>48 square feet.

The area after the decrease in the dimensions is </span><span>24 square feet​ .

24 is half of 48, so the area decreased by half, that is by 50%


Answer: </span>50%
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Perform the indicated operation.(3/a+2) + (4/a-5)
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Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

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marissa [1.9K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

  • The rule for Converse is: Interchange the two statements.
  • The rule for Inverse is: Negative both statements.
  • The rule for Contrapositive is: Negative both statements and interchange them.

Part (A) If it snows tonight, then I will stay at home.

Here p is If it snows tonight, and q is I will stay at home.

Converse: If I will stay at home then it snows tonight.

q \rightarrow p

Inverse: If it doesn't snows tonight, then I will not stay at home.

\sim p \rightarrow \sim q

Contrapositive: If I will not stay at home then it doesn't snows tonight.

\sim q \rightarrow \sim p

Part (B) I go to the beach whenever it is a sunny summer day.

Here p is I go to the beach, and q is it is a sunny summer day.

Converse: It is a sunny summer day whenever I go to the beach.

q \rightarrow p

Inverse: I don't go to the beach whenever it is not a sunny summer day.

\sim p \rightarrow \sim q

Contrapositive: It is not a sunny summer day whenever I don't go to the beach.

\sim q \rightarrow \sim p

Part (C) When I stay up late, it is necessary that I sleep until noon.

P is I sleep until noon and q is I stay up late.

Converse: If I sleep until noon, then it is necessary that i stay up late.

q \rightarrow p

Inverse: When I don't stay up late, it is necessary that I don't sleep until noon.

\sim p \rightarrow \sim q

Contrapositive: If I don't sleep until noon, then it is not necessary that i stay up late.

\sim q \rightarrow \sim p

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Answer:

(4×4)_7

16_7

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