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3 years ago

1 5/8 divide 1.625= what

Mathematics

1 answer:

adoni [48]3 years ago

6 0

Actually:

1 5/8 simplifies to 1.625. Do 5.8 and get 0.625 then add 1. Its 1.625. So 1.625/1.625=1. Its the same thing with mixed number. (1 5/8) / 1.625 = 1

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WILL MARK BRAINLIEST + 10 POINTS<br> #14

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3 years ago

Help with number 14 please :))

Degger [83]

Answer:

b = - 5

Step-by-step explanation:

(k + a )(k + x) + 1 = k^2 + kx + ak + ax + 1

I think the way to solve this is to worry about the 36

k^s + 1 + ak should equal 36

We know that a = 2

k^2 + 1 + 2k = 36

k^2 + 2k + 1 - 36 = 0

k^2 + 2k - 35 = 0

(k + 7)(k - 5) = 0

k = -7 is the only acceptable answer. It is given that K < 0.

bx = kx + ax

b = k + a

b = - 7 + 2

b = - 5

3 0

2 years ago

For her book club, Sharon reads for 45 minutes each day. Write an expression for the number of hours she reads in d days?

VMariaS [17]

H=45d h stands for hours and 45d means 45 minutes per day

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2 years ago

Read 2 more answers

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

-1 3/5 divided by -2/3 written as mixed number

blondinia [14]

First, you must change all of this into improper fractions, like shown below.
$- \frac{8}{5}\div - \frac{2}{3} =$
Now you must change the sign.
$- \frac{8}{5}* - \frac{2}{3} =$
Then we must reciprocalize 2/3.
$- \frac{8}{5}* - \frac{3}{2} =$
Now we multiply, to get 2 4/10.

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2 years ago