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sveta [45]
3 years ago
15

7 points

Mathematics
1 answer:
inna [77]3 years ago
5 0

Answer:

Step-by-step explanation:

Let x be a random variable representing the products are rejected

because they contain some technical

problems. This is a binomial distribution since the outcomes are two ways. It is either they are rejected or accepted. The probability of success(that they would be rejected), p = 0.2

The probability of failure, q would be 1 - p = 1 - 0.2 = 0.8

n = 11

a) We want to determine P(x < 3)

From the binomial distribution table,

P(x < 3) = 0.62

b) We want to determine P(x ≥ 3)

From the binomial distribution table,

P(x ≥ 3) = 0.38

c) The number of rejects that the sample is expected to contain is the mean.

mean = np

mean = 11 × 0.2 = 2.2

Approximately 2 rejects

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Solution:

Two trains are moving in opposite direction with Speed 40 kmph and 60 kmph. Make train B stationary and then take the Speed of train A relative to the train B. So relative Speed of train A = 40 + 60 = 100 kmph. Before it crashes into the stationary train B it has to travel a Distance of 200 m which it will do in (0.2/100 ) hours. During this duration, the average Speed of bird has been 10 kmph i.e. before the crash total Distance covered by the bird = 0.2 * 10/100 km = 20 meters.
Hope it helps
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3 years ago
In the accompanying figure, triangle ABC has coordinates A(0,3), B(7,3), C(7,7). What is the area of triangle ABC in square unit
lora16 [44]

Look at the picture.

A_\triangle=\dfrac{bh}{2}

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5 0
3 years ago
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Ms. Williams 7th grade class goes
photoshop1234 [79]

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4 years ago
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Consider the planes 4x+3y+4z=1 and 4x+4z=0. (A) Find the unique point P on the y−axis which is on both planes. ( 0 equation edit
Nana76 [90]

Answer:

Step-by-step explanation:

A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,

1=4x+3y+4z = 3y + (4x+4z)= 3y+0.

From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).

B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.

\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k

As we want a unit vector, we must calculate the modulus of u:

|u|=\sqrt{12^2+0^2+12^2} = \sqrt{2\cdot 12^2}=12\sqrt{2}.

Thus, the wanted vector is \frac{u}{12\sqrt{2}}. Therefore,

u = \frac{1}{\sqrt{2}}i-\frac{1}{\sqrt{2}}k = \frac{\sqrt{2}}{2}i-\frac{\sqrt{2}}{2}k.

C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.

r = \frac{1}{3}j +\lambda \left( \frac{\sqrt{2}}{2}i- \frac{\sqrt{2}}{2}k \right)

where \lambda is a real number.

8 0
4 years ago
2 3/4 written as fraction greater than one
sladkih [1.3K]
2 3/4 = 11/4 <=== written as an improper fraction
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4 years ago
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