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3 years ago

Please anawer this question me mark branliest

Mathematics

1 answer:

Crank3 years ago

6 0

The answer is c. Because there are 3 times more blank marbles than white marbles.

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Please help me with this question I also need to see the steps if possible!

umka21 [38]

Hi there!

To solve, we must use the following trig identity:

sin(u - v) = sin(u)cos(v) - sin(v)cos(u)

We can rewrite the left hand side of the equation as:

$\frac{sin(u)cos(v)-sin(v)cos(u)}{sin(u)cos(v)}$

Split the fraction:

$\frac{sin(u)cos(v)}{sin(u)cos(v)} - \frac{sin(v)cos(u)}{sin(u)cos(v)} =$

First fraction reduces to 1:

$1 - \frac{sin(v)cos(u)}{sin(u)cos(v)} =$

Simpify each with common arguments:

$1 - tan(v)cot(u)$

4 0

3 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

3 years ago

Graph the Rarabola.---Plot five points on the parabola: the vertex, two points to the left of the vertex, and tvbutton2Explanati

valentinak56 [21]

Which parabola?

$y=-x^2$

Equation of the parabola

y - y1 = 4p(x - x1)

The Vertex of the parabola given is (0, 0) because it does not have the values of x1 and y1.

Then Vertex = (0,0)

-Look for two values of y to the left and two points to the right.

You can choose the points that you which

x y

-3 y = -(-3)^2 = -9

-1 y = -(-1)^2 = -1

0 y = -(0)^2 = 0

1 y = -(1)^2 = -1

3 y = -(3)^2 = -9

3 0

1 year ago

jim’s percentile rank in a class of 50 students was the 92nd. what was his rank in the class (1st = best, 2nd = second best, etc

dezoksy [38]

Jim is ranked third best in his class of 50 students.

4 0

3 years ago

FREE POINTS

Nonamiya [84]

2 please pick me!!!!

5 0

3 years ago

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