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jeka94
3 years ago
6

What is 1 plus 1 what is t6he sum of that

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

2

just trust me

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Paula's house is assessed at $213,000, and her property tax rate is 2.9%. How
NARA [144]

Answer:A

Step-by-step explanation:

She is taxed at a rate of 2.9%, so each year she is taxed 213000 * 2.9% . calculating this, we find that every year, she must pay 6177 in taxes. However, we need the amount in a month, so we divide by 12, to get 6177/12= 514.75, or A

3 0
3 years ago
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Which equation is an identity?
Yakvenalex [24]
C. 3w + 8 - w = 4w - 2(w - 4)

(3w - w) + 8 = 4w - 2w -2(-4)

2w + 8 = 2w + 8
8 0
2 years ago
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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Exercise 1.2 1 Round each of these numbers to the degree of accuracy shown in brackets. a) 7765 (nearest hundred). b) 1099 (near
wlad13 [49]

Answer:

a. 700

b. 1000

c. 80

d. 700

e.

6 0
1 year ago
Please help me with this
4vir4ik [10]

Answer:

3, 8, 12, 12, 14, 20, 21, 23, 26, 34

stem         leaf

0               3     8

1                 2     2       4               (you have 12,12,14)

2                0      1       3        6    ( numbers 20,21,23,26)

3                 4                               ( number 34)

6 0
3 years ago
Read 2 more answers
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