5/6 divided by 6.5
Convert decimal into fraction
5/6 divided by 13/2
Multiply by reciprocal
5/6 times 2/13
Reduce the numbers using Greatest Common factor which is 2
5/3 times 1/13
Multiply the fractions
5/39
Final answer
x⁴ + 4x³ + 4x² = -16x
x⁴ + 4x³ + 4x² + 16x = -16x + 16x
x⁴ + 4x³ + 4x² + 16x = 0
x(x³) + x(4x²) + x(4x) + x(16) = 0
x(x³ + 4x² + 4x + 16) = 0
x(x²(x) + x²(4) + 4(x) + 4(4)) = 0
x(x²(x + 4) + 4(x + 4)) = 0
x(x² + 4)(x + 4) = 0
x = 0 U x² + 4 = 0 U x + 4 = 0
<u> - 4 - 4</u> <u> - 4 - 4</u>
x² = -4 x = -4
x = <u>+</u>2i
The solution set is equal to {-4, -2i, 0, 2i}.
Answer:
h = 5
Step-by-step explanation:
h/2+1/2=3
Multiply each side by 2 to get rid of the fractions
2(h/2+1/2)=3*2
h+1 = 6
Subtract 1 from each side
h+1-1 = 6-1
h = 5
We could say that every 2 years, Patrick gains 7 kg (after reaching a certain age under 12) making it
7(y/2) (if y = every year after the age given, and we divide by 2 because it's every 2 years, not one)+w (patrick's weight at the start)= w (weight)
B- We could say that w(current weight)+100000=b (new weight)
C - If patrick weighed 43 kg when he was 12 , how much would he weigh when he was 20?
D - Using the correct equation, we have 7(20/2-12/2)+43=7(4)+43=28+43=61
Using the incorrect equation, we have 43+100000=100043 kg
Answer:
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