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scoundrel [369]

3 years ago

11

4) 8x+4y=-8 -x + 4y = -17

1 answer:

horrorfan [7]3 years ago

8 0

Answer:

x=1

y=-4

Step-by-step explanation:

find x by making y to 0
sub x into equation
find y

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Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

3 years ago

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KatRina [158]

The answer to your problem is 360

8 0

3 years ago

Read 2 more answers

Need help ASAPPPPPPP

patriot [66]

Answer:

8 is the correct answer because coefficient lies before Exponent. Exponent is variable

So 8 is the coefficient.

5 0

2 years ago

What is the value of x?<br><br> sin49° = cosx<br><br> Enter your answer in the box.<br><br> x = ? °

Anni [7]

Answer:

$x = 41^{\circ}$

Step-by-step explanation:

$\sin(49^{\circ}) = \cos(90^\circ -49^\circ) = \cos (41^\circ)$

3 0

3 years ago

Question 7 of 10

Ganezh [65]

Answer:

Option B

Step-by-step explanation:

Given Equation :

$\qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2$

Using distribute property:

$\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2$

Adding the like terms we get :

$\qquad \sf \dashrightarrow \: 12x + 9 = 2x + 5x - 15 + 2$

$\qquad \sf \dashrightarrow \: 12x + 9 = 7x - 13$

Transposing the variables on the right side and constant terms on the left side :

$\qquad \sf \dashrightarrow \: 12x - 7x = - 13 - 9$

$\qquad \sf \dashrightarrow \: 5x = - 22$

Dividing both sides by 5 :

$\qquad \sf \dashrightarrow \: \dfrac{5x}{5} = \dfrac{ - 22}{5}$

$\qquad \bf \dashrightarrow \: x = \dfrac{ - 22}{5}$

3 0

2 years ago