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Usimov [2.4K]
4 years ago
15

Convert 2910 to binary, hexadecimal and octal. Convert 5810 to binary, hexadecimal and octal. Convert E316 to binary, decimal an

d octal. Convert 5916 to binary, decimal and octal. Convert 010010102 to decimal, octal and hexadecimal. Convert 001010102 to decimal, octal and hexadecimal. Convert 438 to binary, decimal and hexadecimal. Convert 618 to binary, decimal and hexadecimal.
Computers and Technology
1 answer:
Burka [1]4 years ago
5 0

Answer:

2910 to binary = 101101011110

2910 to hexadecimal = B5E

2910 to octal = 5536

E316 to binary = 1110001100010110

E316 to octal = 161426

E316 to decimal = 58134

5916 to binary = 101100100010110

5916 to decimal = 22806

5916 to octal = 54426

010010102 to decimal = 149

010010102 to octal = 225

010010102 to hexadecimal = 95

FOR 438 and 618, 8 is not a valid digit for octal..

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Rectangle perimeter is 72 .Find the new perimeter if length is doubled and breadth is tripled​
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A method countDigits(int num) of class Digits returns the remainder when the input argument num(num > 0) is divided by the nu
sertanlavr [38]

Answer:

#include <iostream>

using namespace std;

class Digits

{

   public:

   int num;

   int read()       //method to read num from user

   {

       cout<<"Enter number(>0)\n";

       cin>>num;

       return num;

   }

   int digit_count(int num)  //method to count number of digits of num

   {

       int count=0;

       while(num>0)    //loop till num>0

       {

           num/=10;

           count++;   //counter which counts number of digits

       }

       return count;

   }

   int countDigits(int num)   //method to return remainder

   {

       int c=digit_count(num); //calls method inside method

       return num%c;  

   }

};

int main()

{

   Digits d;    //object of class Digits is created

   int number=d.read();   //num is read from user

   cout<<"\nRemainder is : "<<d.countDigits(number);  //used to find remainder

   return 0;

}

Output :

Enter number(>0)

343

Remainder is : 1

Explanation:

As program is missing to find errors , a logically write program is written to find the remainder when a number is divided by its number of digits. A class  Digits is constructed which has public variable num and methods read(), digit_count(), countDigits().

  • read() - This method reads value of num from the user and return num.
  • digit_count() - This method takes a integer as parameter and counts the number of digits of a number passed as argument. while loop is used to increement the counter until num<0. This returns the value of count.
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At last in main method , object of Digits class is created and its methods are used to find the output.

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4 years ago
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Answer:

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Output:

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