Answer:
Following python statement will give the assignment to testResult as specified:
if((geneticMarkerA == 1) or (geneticMarkerB ==1)):
testResult = 1
if((geneticMarkerA ==1) and (geneticMarkerB == 1)):
testResult = 0
if((geneticMarkerA == 0) and (geneticMarkerB == 0)):
testResult = 0
Explanation:
In above statements or and and operator are used to check the conditions of set of values present in variable geneticMarkerA and geneticMarkerB.
Based on if the condition evaluate to true or false respective values to testResult varaible is assigned.
Following is sample run for above statements:
geneticMarkerA = 1
geneticMarkerB = 0
if((geneticMarkerA == 1) or (geneticMarkerB ==1)):
testResult = 1
if((geneticMarkerA ==1) and (geneticMarkerB == 1)):
testResult = 0
if((geneticMarkerA == 0) and (geneticMarkerB == 0)):
testResult = 0
print(testResult)
Output
1
Answer:
Pong
Explanation:
In 1958, a physicist created a tennis game in which he found the very first video game.
Answer:
False
Explanation:
Namecoin is a type of crypto currency which was originally pronged from Bitcoin software. It is coded in the fashion of Bitcoin with the same algorithm as well. Hence it is not a blockchain technology that is used to implement decentralized version of Routing Banking System. Namecoin can store data within its own blockchain transaction database.
Answer:
4.01 version .
Explanation:
A hypertext Markup language is used for designing the web page when we added the CSS on the web page we can create the web page more efficient manner and also there is more control over the web page because we can easily call the classes of CSS.
The Hypertext Markup language version 4.01 provides greater flexibility on the web page also We can also control the page layout in a very easy manner. The appearance of the web page is good as compared to version HTML 4
Answer:
Explanation:
The following code is a Python function that takes in the amount of change. Then it uses division and the modulo operator to calculate the number of coins that make up the changes, using the greatest coin values first.
import math
def amountOfCoins(change):
print("Change: " + str(change))
quarters = math.floor(change / 0.25)
change = change % 0.25
dimes = math.floor(change / 0.20)
change = change % 0.20
pennies = math.floor(change / 0.01)
print("Quarters: " + str(quarters) + "\nDimes: " + str(dimes) + "\nPennies: " + str(pennies))
