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poizon [28]
3 years ago
14

A ____ is a type of program that uses a grid to organize and work with data.

Computers and Technology
1 answer:
VLD [36.1K]3 years ago
4 0

Question: A ____ is a type of program that uses a grid to organize and work with data.

Answer: cells

Explanation: cells store data and other things in columns and organize them


Question: Explain how to create a Pivot table?

Answer:  1.Click a cell in the source data or table range.

2.Go to Insert > Recommended PivotTable.

3.Excel analyzes your data and presents you with several options, like in this example using the household expense data.

4.Select the PivotTable that looks best to you and press OK.

question answered by

(jacemorris04)

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Which one of these tasks is part of the pre-production phase of game development?
Alexxx [7]
[B], developing the art style guide and production plan.

It wouldn't be [A], because patches are released to consumers of the game, to fix bugs and add new content, which won't be done until post-production.

It wouldn't be [C] either, as it is also post-production, because you are sending the game to produced, packaged and shipped, meaning the game has already been pretty much fully developed.
3 0
3 years ago
Read 2 more answers
Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither.
Volgvan

Question:

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers.

Answer:

Written in Python

listlent = int(input("Length of List: "))

mylist = []

mylist.append(listlent)

for i in range(listlent):

    num = int(input(": "))

    mylist.append(num)

<em>    </em>

evens = 0

odds = 0

for i in range(1,listlent+1):

    if mylist[i]%2==0:

         evens=evens+1

    else:

         odds=odds+1

       

if(evens == 0 and odds != 0):

    print("All Odds")

elif(evens != 0 and odds == 0):

    print("All Even")

else:

    print("Neither")

Explanation:

This prompts user for length of the list

listlent = int(input("Length of List: "))

This initializes an empty list

mylist = []

The following iteration reads the list items from the user

<em>mylist.append(listlent)</em>

<em>for i in range(listlent):</em>

<em>     num = int(input(": "))</em>

<em>     mylist.append(num)</em>

   

The next two lines initialize even and odd to 0, respectively

<em>evens = 0</em>

<em>odds = 0</em>

<em />

The following iteration if a list item is even or odd

<em>for i in range(1,listlent+1):</em>

<em>     if mylist[i]%2==0:</em>

<em>          evens=evens+1</em>

<em>     else:</em>

<em>          odds=odds+1</em>

This checks and prints if all list items is odd        

<em>if(evens == 0 and odds != 0):</em>

<em>     print("All Odds")</em>

This checks and prints if all list items is even        

<em>elif(evens != 0 and odds == 0):</em>

<em>     print("All Even")</em>

This checks and prints if all list items is neither even nor odd

<em>else:</em>

<em>     print("Neither")</em>

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Answer:

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Explanation:

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