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Nikitich [7]
3 years ago
8

The exterior angles of a triangle measure x + 3, 2x + 1, and 3x - 4. Find the measure of each exterior angle. A) 18°, 31°, and 4

1° B) 23°, 41°, and 56° C) 33°, 61°, and 86° D) 63°, 121°, and 176°
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0
<span>We know that, the sum of the exterior angles of a polygon is 360 i.e., (x+3) + (2x+1) +(3x-1) = 360 i.e., x+2x+3x+3+1-4 = 360 i.e., 6x = 360 Therefore, x = 60 Now, x+3 = 60+3 =63 2x+1 = 2*60 +1 =120 + 1 = 121 3x-4 = 3*60 - 4 = 180 - 4 = 176 The exterior angles are 63, 121 and 176</span>
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During a period of extreme cold, the average daily temperature dropped decreased by 1. Feach day. How many days did it take for
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From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
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