We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.






Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is
.
Therefore, the radius of given circle would be 18 cm.
Answer:
I really don't know so sorry
<h3>Answer : </h3>

<h3>Solution :</h3>

By taking LCM = 4 × 9 = 36





Answer:
three <em>multipl</em><em>i</em><em>e</em><em>d</em><em> </em>by six <em>m</em><em>i</em><em>n</em><em>u</em><em>s</em><em> </em>one in <em>parentheses</em><em> </em>
Step-by-step explanation:
For the last part aka (6-1) just say that 6-1 is in parenthesis
Hope this helpss!! :DD♡
Answer:23 And 24
Step-by-step explanation:
((37 - (−√(−24))) - (−√(37))) - 24 =
19.0827625 + 4.89897949 i
19.0827625
+ 4.89897949
23.98174199
23.98174199 is between 23 and 24