The 2-point form of the equation of a line can be written as ...
... y = (y2-y1)/(x2-x1)·(x -x1) +y1
For your points, this is ...
... y = (1-5)/(3-6)·(x -6) +5
... y = (4/3)(x -6) +5
It can also be written as
... y -5 = (4/3)(x -6)
-4,. 3
or. ±4/1,. ±2/1,. ±1/1,. ±4/3,. ±2/3,. ±1/3,.
Answer:
m∠KHL = 43°
Step-by-step explanation:
From the picture attached,
m∠KHL ≅ m∠GHL [Given in the picture]
Now substituting the values of the angles,
(3x + 1) = (5x - 27)
1 + 27 = 5x - 3x
28 = 2x
14 = x
m∠KHL = (3x + 1)° = (3 × 14) + 1
= 42 + 1
= 43°
Therefore, measure of ∠KHL = 43°
17. 2x<16 x=7 or lower
All I can help you with is #17,
sorry that I can't answer the other 3.
I hope this helped! :-)
