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Varvara68 [4.7K]
3 years ago
9

None of the three planes intersect: none of the three planes intersect 2. the three planes intersect in one line: the three plan

es intersect in one line 3. the three planes intersect in one point: the three planes intersect in one point 4. two planes do not intersect. the third plane intersects the other two.: two planes do not intersect. the third plane intersects the other two. 5. exactly two planes intersect. the third plane does not intersect the other two.: exactly two planes intersect. the third plane does not intersect the other two.
Mathematics
1 answer:
NeX [460]3 years ago
3 0
I need the answer too
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The value of n. 3n = (3^2)8
cupoosta [38]

Answer:

n= 24

because 3*24=72

and  (3^2)8 = 9*8=72

8 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
Julie has the three segments shown in the graph. Can she make a triangle with these segments.
bagirrra123 [75]

Answer:

D

Step-by-step explanation:

5 0
4 years ago
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Twice a year, the P.E. teachers test the fitness level of all sixth grade students at Walker Middle School. The students' weight
Bezzdna [24]

A, D, E; and F: The weights of 6th grade boys, how many 6th graders there are, the shortest height of the sixth graders, and how many pushups a sixth grade girl can do.. as these all stay relevant to the data provided
3 0
3 years ago
9n+21−3n−24 simplify
Thepotemich [5.8K]
Alright First you combine the like terms. 
9n - 3n = 6n 
21 - 24 = -3 

Rewrite the simplified equation
6n - 3 = 0

Solve for n 
6n = 3 
n = 3/6 
n = 1/2 

Ask if you need more help! :)

6 0
3 years ago
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