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Paraphin [41]
3 years ago
15

Six books are to be placed in a 3-tier triangular shelf. How many ways can this be done if the top teir can hold one book, the s

econd tier can hold two books, the third teir can hold three books. (topic: permutation and combination) ​
Mathematics
1 answer:
lawyer [7]3 years ago
5 0

Answer:

you still need answerrrr

Step-by-step explanation:

You might be interested in
Find the measure of angle CED in the figure below. Enter only the number.
nikdorinn [45]

Answer:

∠ CED = 58°

Step-by-step explanation:

∠ CED and ∠ AED are adjacent angles and sum to 180° , then

∠ CED + 122° = 180° ( subtract 122° from both sides )

∠ CED = 58°

6 0
2 years ago
Read 2 more answers
A CD usually sells for $14.00. If the CD is 10% off, and sales tax is 6%, what is the total price of the CD, including tax?
Vikki [24]
10% of 14 =1.4
14-1.4=12.6
6% of 14=0.84
12.6+0.84= 13.45
7 0
3 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
- 3x + 5y = -2<br> 2x - 2y = 1<br> Solve by elem inaction
Lyrx [107]

Answer:

x=1/4 , y=-1/4. You can confirm this by substituting the numbers in.

Step-by-step explanation:

4 0
3 years ago
The volume of the box is 400 inches and the height is 5 inches and it’s 8 inches wide what is the length of the box
levacccp [35]

Answer:

10 inches

Step-by-step explanation:

length=V/WxH

         =400/40

         =10 inches

5 0
2 years ago
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