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lora16 [44]
2 years ago
14

Asap help with this PLEASE

Mathematics
1 answer:
12345 [234]2 years ago
7 0

Answer:

124.5°

Step-by-step explanation:

Let the smallest angle be x. Then, the sum of the angles is an arithmetic sequence with first term x, common difference 7, and 8 terms.

Using the sum of an arithmetic series formula,

\frac{8}{2}(2x+(8-1)(7))=1080 \\ \\ 4(2x+49)=1080 \\ \\ 2x+49=270 \\ \\ 2x=221 \\ \\ x=110.5

So, the third angle is 110.5+14=124.5

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Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17
ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P(V^{C}∩W^{C}) , where P(V^{C}) is the probability that the event V doesn't happen and P(W^{C}) is the probability that the event W doesn't happen.

P(V^{C})= 1-P(V) = 1-0.17 = 0.83

P(W^{C})=1-P(W) = 1-0.05 = 0.95

Since V^{C} and W^{C} aren't mutually exclusive events, then:

P(V^{C}∪W^{C}) = P(V^{C}) + P(W^{C}) - P(V^{C}∩W^{C})

Isolating the probability that interests us:

P(V^{C}∩W^{C})= P(V^{C}) + P(W^{C}) - P(V^{C}∪W^{C})

Where P(V^{C}∪W^{C}) = 1 - 0.04 = 0.96

Finally:

P(V^{C}∩W^{C}) = 0.83 + 0.95 - 0.96 = 0.82

5 0
3 years ago
What is the Area of the parallelogram
ikadub [295]

Answer:

55

Step-by-step explanation:

The Distance between (-2, -5) and (-2, 6) is 11 and the distance between (-2, 5) and (3, 5) [the altitiude] is 5. 11 x 5 is 55 so therefore the area is 55 :)

4 0
2 years ago
Read 2 more answers
Simplify:<br> -11√21-11√/21
alex41 [277]

Step-by-step explanation:

by using the radical and suds rule

6 0
2 years ago
You want to wrap a gift shaped like the regular triangular prism shown. How many
kotegsom [21]

Answer:

697.6 \ in^2

Step-by-step explanation:

-Given the dimensions of the box is 8.7 in, 14 in and 10 in.

Let length=14 in, width=10 in and height =8.7 in

#The surface area of a rectangular prism is calculated as:

Surface \ Area=2(wl+hl+hw)\\\\l=length, w=width, h=height\\\\\therefore Surface \ Area=2(14\times 10+10\times 8.7+14\times 8.7)\\\\=697.6 \ in^2

Hence, the wrapping paper needed has an area of 697.6 \ in^2

8 0
3 years ago
#4- A baby weighed 7.6 pounds at birth and 9 1/2 pounds after 6 Weeks. What was the percent increase?
ivanzaharov [21]
The pounds increased 1.6 hope this helped
3 0
3 years ago
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