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3 years ago

Please help me I’m desperate

Mathematics

1 answer:

Dafna1 [17]3 years ago

4 0

Answer:

<h2> The first</h2>

Step-by-step explanation:

$\frac29x+3>4\frac59\\{}\quad-3\quad-3\\\\\frac29x\ >\ 1\frac59\\\div\frac29\quad \, \div\frac29\\\\x>1\frac59\div\frac29\\\\x>\frac{14}9\times\frac92\\\\x>\frac{7}1\times\frac11\\\\x>7$

That means every x wich is greater than 7

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What is the HCF and LCM of 268 and 244

Ray Of Light [21]

Answer:

HCF = 4

LCF = 16348

HOPE THIS HELPS :)

5 0

2 years ago

An analyst from an energy research institute in California wishes to precisely estimate a 99% confidence interval of the average

Lena [83]

Answer:

190

Step-by-step explanation:

Data provided in the question:

Confidence level = 99%

Therefore,

α = 1% = 0.01

[ from standard normal table ]

z-value for $z_{\frac{\alpha}{2}}= z_{\frac{0.01}{2}}=$ = 2.58

Margin of error, E = $0.06

Standard deviation, σ = $0.32

Now,

n = $(\frac{z_{0.005}\sigma}{E})^2$

Here,

n is the sample size (or the minimum number of gas stations )

on substituting the respective values, we get

= $(\frac{z_{0.005}\sigma}{E})^2$

= $(\frac{2.58\times0.32}{0.06})^2$

= 13.76²

= 189.3376 ≈ 190

Hence,

minimum number of gas stations that she should include in her sample is 190

5 0

3 years ago

The line that passes through the points (9,1) and (5,5) intersects the y-axis at (0,5).

Ilia_Sergeevich [38]

The stament are true I think

6 0

3 years ago

11b-12<-100

ruslelena [56]

Answer:

ok wait which symbol? this (<)?

well it should stay the same since -100 is greater than the 11b-12

LHS=RHS

11b÷11b b must cancell b also do the same on -12. -12÷11 will give u a lesser value compared to -100

prove me wrong

4 0

2 years ago

Read 2 more answers

Pre-Cal Help?!?! Solve e^x^2-9=1

andrey2020 [161]

E^x^2 - 9 = 1
e^x^2 = 1 + 9 = 10
Ln e^x^2 = Ln 10
x^2 = Ln 10
x = sqrt (Ln 10) = 1.517
x = 1.517

5 0

3 years ago