Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
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Answer:
600
Step-by-step explanation:
math
6.2 x 10^-3
Because when you add them together you get .0062 so you don't want anymore than one number to the left of decimal when in scientific notation therefore its 6.2 so you wanna move the decimal three spaces to the left to get .0062 therefore its 6.2x10^-3
Answer:
<u>See below:</u>
Step-by-step explanation:
Let the angles be 5x , 4x , 3x.[Since the angles are in ratio 5:4:3 ] respectively.
We know that sum of all angles of a triangle is 180°.
So,

Now Find the value of x of this equation.





Now,
Multiply each ratio given by 15 which is the value of x we got.
That is;



Hence,the measurements of the angles of the triangle would be 75°[First Angle],60°[Second angle],and 45° [Third Angle].

I hope this helps!
Let me know if you have any questions.