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4 years ago

It must be least to greatest

Mathematics

1 answer:

stiv31 [10]4 years ago

4 0

-5 1/3, 2 1/2, 3.75 that is all i can see in the picture

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I need help with one and two please!

Dmitrij [34]

Answer:

Step-by-step explanation:

7 0

3 years ago

TIS IS TIMEDDD PLS ANSWER WILL GIVE BRAINLISTTTTT......

DedPeter [7]

Answer: well, just multiply x and y by the scale factor

Step-by-step explanation:A square with a perimeter of 20 units is graphed on a coordinate grid. The square is dilated by a scale factor

of 0.4 with the origin as the center of dilation.

If (x, y) represents the location of any point on the original square, which ordered pair represents the

coordinates of the corresponding point on the resulting square.

GIVE ME DA BRAINS

3 0

3 years ago

Write a two operation expression that equals 31 when evaluated for x=5

RSB [31]

X*6+1=31

5*6=30
30+1=31

x*7-4=31

5*7=35
35-4=31

Hope this helps! If you have any questions, just ask me!

5 0

4 years ago

Which of the following is a rational number <br> sqaureroot 17 <br> 1/2 <br> squareroot 8 <br> pi

Nitella [24]

1/2 is a rational no.

8 0

4 years ago

Read 2 more answers

What is the sum of the series? 4 ∑k=1 (2k^2−4)

larisa86 [58]

The sum of the series $\sum_{k=1}^{4}\left(2 k^{2}-4\right)$ is 44.

Step-by-step explanation:

The given series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

To find the sum of the series, we need to substitute the values for k in the series.

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]$

Now, simplifying the square terms, we get,

$[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]$

Multiplying the terms,

$[2-4]+[8-4]+[18-4]+[32-4]$

Subtracting the values within the bracket term, we get,

$-2+4+14+28$

Now, adding all the terms, we get the sum of the series,

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

Thus, the sum of the series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

8 0

3 years ago