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3 years ago

It must be least to greatest

Mathematics

1 answer:

stiv31 [10]3 years ago

4 0

-5 1/3, 2 1/2, 3.75 that is all i can see in the picture

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Please help me asap!!

snow_lady [41]

Answer:

x is 9

Step-by-step explanation:

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2 years ago

What would you do if u got hurt really bad and how would u deal with it???? 5 sentences

patriot [66]

Answer:

1.) Pray to Jesus. 2.) Go to the nurse, she'll give you an mint. 3.) If you're lucky an ice pack. 4.) Rethink life decisions. 5.) Go back to classroom

Step-by-step explanation:

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2 years ago

Read 2 more answers

What is the value of 5 in 756 write and draw to explain how you know?

kykrilka [37]

In the attached diagram you can see Place Value Chart that is used to help understand the value of each digit based on the place or position.

For the number 756:

7 has a value of 7 hundreds, or 700;
5 has a value of 5 tens, or 50;
6 has a value of 6 ones, or 6.

Answer: 5 has a value of 5 tens, or 50

8 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP ME

Alexus [3.1K]

Y=-2x-2 it is the only one that is perfectly perpendicular and passes through (-3,4)

3 0

2 years ago

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

5 0

2 years ago